C＃比较两时间大小
1、比较时间大小的实验
    string st1="12:13";
    string st2="14:14";
    DateTime dt1=Convert.ToDateTime(st1);
    DateTime dt2=Convert.ToDateTime(st2);
    DateTime dt3=DateTime.Now;
    if(DateTime.Compare(dt1,dt2)>0)
     msg.Text=st1+">"+st2;
    else
     msg.Text=st1+"<"+st2;
    msg.Text+=" "+dt1.ToString();
    if(DateTime.Compare(dt1,dt3)>0)
     msg.Text+=" "+st1+">"+dt3.ToString();
    else
     msg.Text+=" "+st1+"<"+dt3.ToString();
2、计算两个时间差值的函数，返回时间差的绝对值：
         private string DateDiff(DateTime DateTime1,DateTime DateTime2)
         {
             string dateDiff=null;
             try
             {
                 TimeSpan ts1=new   TimeSpan(DateTime1.Ticks);
                 TimeSpan ts2=new   TimeSpan(DateTime2.Ticks);
                 TimeSpan ts=ts1.Subtract(ts2).Duration();
                 dateDiff=ts.Days.ToString()+"天"
                         +ts.Hours.ToString()+"小时"
                         +ts.Minutes.ToString()+"分钟"
                         +ts.Seconds.ToString()+"秒";
             }
             catch
             {
             }
             return dateDiff;
         }
3、实现计算DateTime1－36天＝DateTime2的功能
    TimeSpan ts=new TimeSpan(40,0,0,0);
    DateTime dt2=DateTime.Now.Subtract(ts);
    msg.Text=DateTime.Now.ToString()+"-"+ts.Days.ToString()+"天 ";
    msg.Text+=dt2.ToString();